Here's a difficult problem of proving that a given expression is not a perfect square. A direct approach will be a nightmare ( even not sure it can be proved) but use of a simple property of perfect squares will ease the problem. We know that any perfect squares leaves a remainder either 1 or 0 when being divided by 3 or 4. This simple result would be used to solve the problem.
Solved Problems: Indian Statistical Institute (ISI), Chennai Mathematical Institute (CMI), IIT-JEE Main & Advance, and Olympiads (RMO/INMO). Entrance Exam Solutions: Solved Problems for ISI B.Math/B.Stat, CMI, JEE (IIT), Olympiads, and CBSE/ISC/ICSE Mathematics Board Papers. Practice Problems and Chapter Test on various topics for CBSE, ICSE, Madhyamik, HS and ISC students
Wednesday, October 23, 2019
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