Inverse Laplace Transformation

 In mathematics, the Laplace transform, named after its inventor Pierre-Simon Laplace is an integral transform that converts a function of a real variable  (often time) to a function of a complex variable  (complex frequency). The transform has many applications in science and engineering because it is a tool for solving differential equations. In particular, it transforms differential equations into algebraic equations and convolution into multiplication.

The Laplace transform of a function f(t), defined for all real numbers t ≥ 0, is the function F(s), which is a unilateral transform defined by

${\displaystyle F(s)=\int _{0}^{\infty }f(t)e^{-st}\,dt}$

(Eq.1)

where s is a complex number frequency parameter

${\displaystyle s=\sigma +i\omega }$, with real numbers σ and ω.

An alternate notation for the Laplace transform is ${\displaystyle {\mathcal {L}}\{f\}}$ instead of F.

Get solution of the following problems.

Evaluate $\mathcal{L} \{ \sin^2 at \}$ $$$$ Evaluate $\mathcal{L} \{ e^{-2t} ( 3\cos 6t - 5 \sin 6t) \}$ $$$$ Evaluate $\mathcal{L} \{ e^{-2t} ( 3\cos 6t - 5 \sin 6t) \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{\alpha}{s-2} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{1}{(s-1)(s-2)} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{3s-2}{s62-4s+20} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{1+s^8}{s^9)} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{s}{s^2+2}+ \frac{6s}{s^2-16}+\frac{3}{s-3} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{1}{(s+2)^2(s-2)} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{1}{s^2-6s+10} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{3s+7}{s^2-2s-3} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{1}{(s+a)^3} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{s}{(s^2-a^2)^2} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{s}{(s^2+a^2)^2} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{s^2}{(s^2+2^2)^2} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{1}{s^2+6s+13} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{1}{(s^2+1)(s^2+4s+5)} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{3s^2+10s+3}{(s^2+1)(s^3+4s62+5s+2)} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{2s+7}{(s+3)^4} \}$ $$$$ Evaluate $\mathcal{L}^{-1} \{ \frac{s+3}{(s^2+4)^2} \}$ $$$$ Download the file below: