Wednesday, July 15, 2020

Problem based on Angle bisector


If AD is the angle bisector of ∠BAC in the triangle ABC. Show that AB.AC=BD.DC+AD^2.

#Solution https://t.me/PrimeMaths/43

#Geometry #PrimeMaths #Angle #Bisectors

Monday, July 13, 2020

Simple but powerful inequality


A very simple but powerful #inequality you must know at #school level! This can be simply proved by the fact that the square of a real number is always non-negative.

incentre of Orthic Triangle:

In ∆ABC, let D, E, F denote the feet of the #altitudes from A, B and C respectively. The DEF is called the #orthic #triangle of ABC. Prove that H is the #incenter of △DEF.







Interesting Property of a Trapezium

Prove that the straight line that passes through the point of intersection of the diagonals of a trapezium and through the point of intersection of its non-parallel sides, bisects each of the parallel sides of the trapezium.


Friday, June 26, 2020

Geometry: Problem involving orthocentre

ABC  is a triangle with AB = 13; BC = 14 and CA = 15. AD and BE  are the altitudes from A and B  to BC and AC respectively. H is the point of intersection of AD and BE. Find the ratio HD/HB. 


Solution: 


Cone on a Sphere : Geometry

A hollow right circular cone rests on a sphere as shown in the figure. The height of the cone is 4 metres and the radius of the base is 1 metre. The volume of the sphere is same as that of the cone. What is the distance between the centre of the sphere and the vertex of the cone?




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