Let z=x+iy, taking the conjugate of the given equation we have (3−7i)¯z+(10+2i)z+100=0
Adding the two equations we get, 26x−18y+200=0 (do the calculations yourself!), this shows that z lies on the line 26x−18y+200=0
Subtracting the two equations we get, 10x−4y=0, this again shows that that z lies on the line 10x−4y=0
Thus z satisfies both the equations 26x−18y+200=0 and 10x−4y=0, thus z represents a point in the Argand Plane.
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