We divide the integers 0≤ai≤9 into three groups having the property that each element of the same group leaves the same remainder on being divided by 3. The groups are {0,3,6,9},{1,4,7}and{2,5,8}. Now a three−tuple (a1,a2,a3) will be divisible by 3 iff and only if each of the co-ordinate belongs to the same group or each of them belongs to the different groups, giving a total of 43+33+33+4×3×3×3!=334 possible three−tuples which are divisible by 3.
Solved Problems for Indian Statistical Institute (B. Math and B. Stat), Chennai Mathematical Institute, JEE Main & Advance ( IIT ) and for Olympiads ( RMO and INMO ). Get Solved problems for boards ( CBSE and ISC Mathematics Papers) along with board papers.
Wednesday, June 10, 2015
Indian Statistical Institute B.Math & B.Stat : Combinatorics
Labels:
ISI
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment